I have a trig question too, cuz I also have an exam coming up.
Convert this polar equation into rectangular form:
r = (sin Θ)(cos Θ)
do eet
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Pretend the a's are thetas, mkay?
r=(sina)(cosa)
r^2=r(sina)(cosa)
y^2+x^2=r(sina)(cosa)
y^2+x^2=x(sina)
y^2+x^2-x(sina)=0
I have no idea if that is correct.
r=(sina)(cosa)
r^2=r(sina)(cosa)
y^2+x^2=r(sina)(cosa)
y^2+x^2=x(sina)
y^2+x^2-x(sina)=0
I have no idea if that is correct.
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