funmachine wrote:
3 logicians walk into a bar. The bartender asks "Does everyone want a beer?"
The first logician says "I don't know."
The second logician says "I don't know."
The third logician says "Yes!"
The first logician says "I don't know."
The second logician says "I don't know."
The third logician says "Yes!"
methamatician wrote:
Explanation: If any one of the three logicians does NOT want a beer, the answer to the bartender's question is "No."
The first logician wants a beer, but doesn't know whether his two friends do. So he says "I don't know."
The second logician now knows that the first logician wants a beer, because if he didn't he would have said no. And though he does want a beer, the he still doesn't know whether the third logician wants a beer. So he says "I don't know."
The third logician now knows that the first two logicians want beer, because otherwise one of them would have said no. So, as he also wants a beer, he now knows that all three logician wants a beer. So he can say "Yes."
Source: I ******* love meth
The first logician wants a beer, but doesn't know whether his two friends do. So he says "I don't know."
The second logician now knows that the first logician wants a beer, because if he didn't he would have said no. And though he does want a beer, the he still doesn't know whether the third logician wants a beer. So he says "I don't know."
The third logician now knows that the first two logicians want beer, because otherwise one of them would have said no. So, as he also wants a beer, he now knows that all three logician wants a beer. So he can say "Yes."
Source: I ******* love meth
Of course, since they are logicians, the first one should have deduced that all three unquestionably would want beer, and so should have said "Yes!".